A crate is pulled up a rough incline. The pulling force is parallel to the incline. The crate is pulled a distance of 6 . 92 m. The acceleration of gravity is 9 . 8 m / s 2. What is the magnitude of the work is done by the gravitational force? Answer in units of J
To find the magnitude of the work done by the gravitational force, we first need to determine the weight of the crate, which is the force exerted by gravity on the crate. The weight can be calculated using the equation:
weight = mass * acceleration due to gravity
Next, we need to calculate the displacement of the crate along the incline. The displacement is given as 6.92 m.
Finally, we can calculate the work done by the gravitational force using the equation:
work = weight * displacement * cos(angle)
where the angle is the angle between the gravitational force and the displacement. Since the pulling force is parallel to the incline, the angle between the gravitational force and the displacement is 0 degrees, and the cosine of 0 degrees is 1.
Therefore, the magnitude of the work done by the gravitational force can be calculated as:
work = weight * displacement * cos(0)
= weight * displacement
Substituting the given values, we get:
work = (mass * acceleration due to gravity) * displacement
Now we have all the necessary information to calculate the magnitude of the work done by the gravitational force.
How far up from earth surface?
6.92 sin theta where theta is the angle up from horizontal
mg opposite to up motion so g does negative work
so - m g sin theta * (6.92)