An ambulance is going away from me @ 40mph with a siren @ 1000Hz.Will I heat a higher or lower frequency
It is going away so you hear a longer wavelength
so LOWER frequency
Use this simplified equation, which is short and dirty method to determine the answer to your question:
f=v/c*(f')
Where
v=-40mph=-17.88m/s
c=3 x 10^8 m/s
f'=1,000Hz
Just eyeballing the numbers, you should see a lower frequency, since v is negative.
I didn't know that you answered the question.
c=360m/s
I gave you the speed of light and not sound.
To determine whether you will hear a higher or lower frequency from the ambulance siren, you need to consider the concept of the Doppler effect. The Doppler effect explains the change in frequency of a wave (in this case, sound) as the source of the wave (the ambulance) moves relative to the observer (you).
In this scenario, the ambulance is moving away from you at 40 mph and has a siren that produces a constant sound frequency of 1000 Hz. Since the ambulance is moving away from you, the sound waves it produces will be stretched out (or elongated), causing a decrease in the perceived frequency.
To calculate the observed frequency, you can use the following formula:
Observed frequency = Source frequency / (1 + (velocity of observer / velocity of sound))
In this case:
Source frequency = 1000 Hz
Velocity of observer (you) = 0 mph (since you are stationary)
Velocity of sound in air = Approximately 343 meters per second or 767 mph
Plug in the values into the formula:
Observed frequency = 1000 Hz / (1 + (0 mph / 767 mph))
Observed frequency = 1000 Hz / (1 + 0)
Observed frequency = 1000 Hz / 1
Observed frequency = 1000 Hz
Therefore, you will hear the same frequency of 1000 Hz from the ambulance, irrespective of its velocity.