Calculate the heat transferred when a 23 g of iron nail is cooled from 67oC to 20oC. The specific heat of iron is 0.45 J/goC.
Refer to your skillet problem.
To calculate the heat transferred when the iron nail is cooled, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat transferred
m is the mass of the iron nail
c is the specific heat of iron
ΔT is the change in temperature
Given:
m = 23 g
c = 0.45 J/goC
ΔT = 67oC - 20oC = 47oC
Now we can substitute the given values into the formula and calculate the heat transferred:
Q = (23 g) * (0.45 J/goC) * (47oC)
Q = 478.35 J
Therefore, the heat transferred when the iron nail is cooled from 67oC to 20oC is 478.35 Joules.