i need help with more questions in the packet heres my question the poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide, NaOH. THE unbalanced equation for this reaction follows:

NaOH(aq)+H2S(g)→Na2S(aq)+H2O(l)
a student who was asked to balance the equation wrote the following Na2OH(aq)+H2S(g)→Na2S(aq)+H3O(l) now i think the student is correct but i don't know and i have to answer my question if the equation is right or not and why.
i have to balance thefollowing equations which is
1.blank C4H10+ blank O2→ blank CO2+ blank H2O NOW I TRIED AND GOT 4C4H10+2O2→1CO2+2H2O
2. IS BLANK C7H6O2+ blank O2→ blank CO2+ blank H20 NOW I TRIED AND GOT 1C7H6O2+2O2→1CO2+1H20
3. BLANK P4O10 + blank H20→ blank H3PO4 I GOT IN THE BLANKS 1,1,1
4. BLANK FeS2+ blank O2→ blank Fe2O3+ blank SO2 I GOT FOR THE BLANKS IS 1,2,2,1
5. MY EQUATION CAME OUT LIKE THIS 1NH3+2O2→1NO+2H2O
6. My equation is this 1Fe+1HCl→2H2+1FeCl2
7. my last equation is this 1Al+2Fe3O4→2Al2O3+1Fe
now i don't know if there right can you please check them and correct them thank you

Let's go through each equation and check if they are balanced correctly:

1. C4H10 + O2 → CO2 + H2O
To balance this equation, we need to have the same number of atoms of each element on both sides. Let's start with the carbon atoms:
On the left side, we have 4 carbon atoms in C4H10, while on the right side, we have only 1 carbon atom in CO2. To balance the carbon atoms, we need to have a coefficient of 4 in front of CO2:
C4H10 + O2 → 4CO2 + H2O

Next, let's check the hydrogen atoms:
On the left side, we have 10 hydrogen atoms in C4H10, while on the right side, we have 2 hydrogen atoms in H2O. To balance the hydrogen atoms, we need to have a coefficient of 5 in front of H2O:
C4H10 + O2 → 4CO2 + 5H2O

Lastly, let's check the oxygen atoms:
On the left side, we have 2 oxygen atoms in O2, while on the right side, we have 4 oxygen atoms in the CO2 and 5 oxygen atoms in the H2O. To balance the oxygen atoms, we need to have a coefficient of 13/2 or 6.5 in front of O2. However, since we cannot have a fraction as a coefficient, we can multiply the entire equation by 2 to get whole number coefficients:
2C4H10 + 13O2 → 8CO2 + 10H2O

So, the correct balanced equation is 2C4H10 + 13O2 → 8CO2 + 10H2O.

2. C7H6O2 + O2 → CO2 + H2O
To balance this equation, we follow the same steps as before:
C7H6O2 + O2 → 7CO2 + 3.5H2O

Again, we cannot have a fraction as a coefficient, so we multiply the entire equation by 2:
2C7H6O2 + 15O2 → 14CO2 + 7H2O

So, the correct balanced equation is 2C7H6O2 + 15O2 → 14CO2 + 7H2O.

3. P4O10 + H2O → H3PO4
This equation is already balanced correctly with the following coefficients:
P4O10 + 6H2O → 4H3PO4

So, the equation is already balanced.

4. FeS2 + O2 → Fe2O3 + SO2
To balance this equation:
2FeS2 + 11O2 → 2Fe2O3 + 4SO2

So, the correct balanced equation is 2FeS2 + 11O2 → 2Fe2O3 + 4SO2.

5. NH3 + O2 → NO + H2O
This equation is already balanced correctly with the following coefficients:
4NH3 + 5O2 → 4NO + 6H2O

So, the equation is already balanced.

6. Fe + HCl → H2 + FeCl2
This equation is already balanced correctly with the following coefficients:
2Fe + 6HCl → 3H2 + 2FeCl3

So, the equation is already balanced.

7. Al + Fe3O4 → Al2O3 + Fe
To balance this equation:
8Al + 3Fe3O4 → 4Al2O3 + 9Fe

So, the correct balanced equation is 8Al + 3Fe3O4 → 4Al2O3 + 9Fe.

I hope this helps! Let me know if you have any further questions.