thirty more student tickets than adult tickets were sold for the game. Student tickets cost $2, adult tickets cost $5 and $1,450 was collected. how many of each kind of ticket were sold

S = A + 30

2S + 5A = 1450

Substitute A+30 for S and solve for A, then S.

To solve this problem, we can set up a system of equations based on the given information.

Let's assume the number of adult tickets sold is 'x'.

According to the problem, the number of student tickets sold is 30 more than the number of adult tickets. So, the number of student tickets sold is 'x + 30'.

Next, let's calculate the total revenue collected from adult and student tickets:

Revenue from adult tickets = x * $5 (the price of one adult ticket)
Revenue from student tickets = (x + 30) * $2 (the price of one student ticket)

According to the problem, the total revenue collected was $1,450. So, we can set up the equation:

x * $5 + (x + 30) * $2 = $1,450

Now, we can solve the equation to find the value of 'x' (the number of adult tickets sold):

5x + 2(x + 30) = 1,450
5x + 2x + 60 = 1,450
7x + 60 = 1,450
7x = 1,450 - 60
7x = 1,390
x = 1,390 / 7
x ≈ 198.57

Since we cannot have a fractional number of tickets, we can assume the number of adult tickets sold to be 198.

Now, we can find the number of student tickets sold:

Number of student tickets = x + 30 = 198 + 30 = 228

Therefore, 198 adult tickets and 228 student tickets were sold for the game.