Sally the bug has an initial speed of 20.0cm/s. She then accelerates at 8.00cm/s^2 for 5.00s.
calculate sallys total displacement? which i did and got 200 cm
Displacement during the 5th second?
can you please help and show all work
To calculate Sally's total displacement during the 5th second, we need to break down the problem step by step.
1. Determine the initial velocity (v) and acceleration (a):
- Sally's initial speed is given as 20.0 cm/s.
- The acceleration is given as 8.00 cm/s^2.
2. Calculate Sally's final velocity (vf) after 5 seconds using the formula:
vf = v + at
where v is the initial velocity, a is the acceleration, and t is the time.
Substituting the known values:
vf = 20.0 cm/s + (8.00 cm/s^2) * (5.00 s)
vf = 20.0 cm/s + 40.0 cm/s
vf = 60.0 cm/s
3. Calculate the displacement (s) during the 5th second using the formula:
s = (v + vf) / 2 * t
where v is the initial velocity, vf is the final velocity, and t is the time.
Substituting the known values:
s = (20.0 cm/s + 60.0 cm/s) / 2 * 5.00 s
s = 80.0 cm/s / 2 * 5.00 s
s = 40.0 cm/s * 5.00 s
s = 200 cm
So, Sally's total displacement during the 5th second is 200 cm.