Paint was stored in three containers of 48 liters, 72 liters and 30 liters . The paint in each container was the repacked into smaller containers. The amount of paint in each of s smaller containers was the same. What was the capacity of the largest container used to repack the paint?

GCF(30,48,72) = 6

To find the capacity of the largest container used to repack the paint, we need to determine the common capacity of the smaller containers.

First, we need to find the greatest common divisor (GCD) of the capacities of the three containers (48 liters, 72 liters, and 30 liters) to determine the common capacity of the smaller containers.

Step 1: Find the GCD of the capacities.
To find the GCD, we can use the Euclidean algorithm.
- GCD(48, 72) = 24 (48 divided by 24 is 2, and 72 divided by 24 is 3).
- GCD(24, 30) = 6 (24 divided by 6 is 4, and 30 divided by 6 is 5).

Step 2: The common capacity of the smaller containers is 6 liters (the GCD).

Therefore, the capacity of the largest container used to repack the paint is 6 liters.