May has 10 fewer marbles than Albert. May has 5 more marbles than Jenny. Albert gives4 marbles to Jenny. May gives another 6 marbles to Jenny. Jenny has 13 marbles now.

Find the number of marbles each of them had at first.
Jenny had 3 marbles.
May had 8 marbles.
Albert had 18 marbles.

Jenny 3 albert 18 may 8

To solve this problem, we can follow the given information step by step and use basic mathematical operations to find the number of marbles each person had initially.

1. Let's start by assuming the number of marbles that Jenny had initially as 'x'.

2. According to the given information, May has 5 more marbles than Jenny. Therefore, the number of marbles May had initially would be 'x + 5'.

3. Albert has 10 more marbles than May. So, the number of marbles Albert had initially would be '(x + 5) + 10'.

4. After that, Albert gives 4 marbles to Jenny, which means Albert now has '(x + 5) + 10 - 4' marbles.

5. Similarly, May gives 6 marbles to Jenny, which means May now has 'x + 5 - 6' marbles.

6. After these transactions, Jenny has 13 marbles. Therefore, we can set up an equation:
'[(x + 5) + 10 - 4] + [x + 5 - 6] + 13 = x'

7. Solving the equation step by step:
'2x + 20 = x + 13'
'x + 20 = 13'
'x = 13 - 20'
'x = -7'

Since it doesn't make sense for Jenny to have a negative number of marbles, we can conclude that there is no solution to this problem based on the given information.

Looks ok to me.