A force of 270N acts on a mass of 13.5kg for 13sec. Calculate a) the acceleration b) the final velocity c) the distance covered.
a)F=m*a, so 270=13.5*a/13, answer 260m/s
b)Not sure which formula.
c)Formula d=v*t, once velocity is worked out in question b).
I am not sure with a) either.
Thank you kindly.
a. F=ma
a= F/m=270/13.5
b. vf= a t
c. d=1/2 a t^2
Thank you.
Can you explain d=1/2 a t^2.
What does the ^ mean?
a) To calculate the acceleration (a), we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). Therefore, rearranging the formula, we have:
a = F / m
Substituting the given values:
a = 270N / 13.5kg
a = 20 m/s^2
So, the acceleration is 20 m/s^2.
b) To calculate the final velocity (v), we can use the formula:
v = u + at
where v is the final velocity, u is the initial velocity (which is not provided in the question), a is the acceleration, and t is the time.
Since the initial velocity is not given, we can assume it to be zero. Therefore, the equation simplifies to:
v = 0 + at
v = 0 + 20 m/s^2 * 13 sec
v = 260 m/s
So, the final velocity is 260 m/s.
c) To calculate the distance covered (d), we can use the equation:
d = ut + (1/2)at^2
Since the initial velocity is zero, the equation further simplifies to:
d = (1/2)at^2
d = (1/2) * 20 m/s^2 * (13 sec)^2
d = 1690 meters
Therefore, the distance covered is 1690 meters.