What force is required to give a 1kg body a velocity of 5m/s after acting for 5sec?
I know I can use F=mxa
What do I do with the 5sec?
Thanks
Yea, you get to use F=MxA
where, M=mass, A=acceleration.
if you expand the equation, you notice
F=MxA
where A=velocity change / time taken for change
therefore, f = 1kg x (5ms/5secs)
The basic form of Newton's second law is
Force = rate of change of momentum
= change of (m V) /time
if m is constant this is the familiar form
F = m dV/dt = m A
but here it is simple to use the more fundamental form
change of momentum/time
= m v/t = 1 *5/5 Newtons
as Francis said.
To find the force required to give a 1kg body a velocity of 5m/s after acting for 5 seconds, you need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Since you are given the mass (m) as 1kg, you can use the equation F = m x a.
To find the acceleration (a), you can use the equation a = change in velocity / time taken.
In this case, the change in velocity is from 0m/s to 5m/s, so it is 5m/s. And the time taken is given as 5 seconds.
So, you can substitute those values into the equation a = change in velocity / time taken:
a = 5m/s / 5s = 1m/s^2
Now that you have the acceleration (a), you can substitute it back into the equation F = m x a:
F = 1kg x 1m/s^2 = 1kg * m/s^2
Therefore, the force required to give a 1kg body a velocity of 5m/s after acting for 5 seconds is equal to 1 Newton (N).