A square has a length of x inches and a width of 2 inches less than the length. If the dimensions
were doubled, what would be the area of the new square in terms of x?
A.(2x-4)in^2
B.(8x-8)in^2
C.(2x^2-4x)in^2
D.(4x^2-8x)in^2
I think D
To find the area of a square, you need to multiply the length of one side by itself. Let's start by finding the original area of the square.
Given that the length of the square is x inches and the width is 2 inches less than the length, the width would be x - 2 inches.
The area of the original square would be x inches (length) multiplied by (x - 2) inches (width).
Area of original square = x * (x - 2)
Now, if the dimensions of the square were doubled, the new length and width would both be 2x inches.
The area of the new square would be 2x inches (length) multiplied by 2x inches (width).
Area of new square = (2x) * (2x) = 4x^2
Therefore, the area of the new square in terms of x is 4x^2 square inches.
The correct answer is D. (4x^2 - 8x) square inches.