What would the graph look like for

y= the absolute value of 2x plus 1

Assuming you meant |2x| + 1,

just like |x|, but squeezed half as wide, and shifted up 1.

In other words a V with 45 degree slopes and point at (0,1)

actually, the slope of the V would be 2, not 1. |x| has slope 1.

Extra credit: what if you had meant y=|2x+1|?

To graph the equation y = |2x + 1|, we can follow these steps:

1. Set up a coordinate plane with x and y axes.
2. Choose some x-values and find the corresponding y-values using the equation.
3. Plot the points on the graph.
4. Draw a smooth curve connecting the plotted points.

Here's how you can find some points to plot:

Start with x = 0:
y = |2(0) + 1| = |1| = 1
So, when x = 0, y = 1. Plot the point (0, 1).

Now, let's find two more points by selecting different x-values:

When x = -1:
y = |2(-1) + 1| = |-2 + 1| = |-1| = 1
So, when x = -1, y = 1. Plot the point (-1, 1).

When x = 1:
y = |2(1) + 1| = |2 + 1| = |3| = 3
So, when x = 1, y = 3. Plot the point (1, 3).

After plotting these points, you can draw a V-shaped graph passing through the points (0,1), (-1,1), and (1,3).