If 3x^2+y^2=7 evaluate ((d^2)y)/(dx^2) when x=1 and y=2
6 x dx + 2 y dy = 0
dy/dx = -3 x/y at (1,2) this is-3/2
d^2y/dx^2 = -3 [ y - x dy/dx ]/y^2
at (1,2) = -3[2+3/2]/4
dy/dx = -3 x/y at (1,2) this is-3/2
d^2y/dx^2 = -3 [ y - x dy/dx ]/y^2
at (1,2) = -3[2+3/2]/4