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Final exam score above 92 corresponds to an A. Approximately what percent of the class got an A?
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Apparently none of them.
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Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The
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what's the problem? Just plug in t=0: S(0) = 68-20log(1) = 68 - 20(0) = 68 Although, as written,
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Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The
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You say your equation is not valid for t=0. Why not? I would assume S(0) = 28 - 20log1 = 28 Note
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when t = 0 S(0) = 68 - 20log(1) = 68 when t= 4 S(4) = 68 - 20log(5) = 54.02... or 54 etc. for score
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There is no question here. There is just an equation.
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.25(92) + .225(83) + .225(94) + .3(84) = ?
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I know the answers I just am not sure how to work the problem to get them. (a)78 (b)67.5 Please help
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We do not do your work for you. However, if you show your work, we will be glad to evaluate it.
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