Eight people are involved in a tug-of-war. The blue team members pull the rope with the forces of
220 N, 340 N, 180 N, and 560 N. Three members of the red team pull it with the forces of 250 N, 160
N, and 420 N. With what force must the fourth person pull the rope to maintain equilibrium?
250+160+420+F4 = 220+340+180+560
Solve for F4.
770
that's what I am asking u no answers ..........what......
fine this the ans...................................................
To solve this problem, we need to find the force that the fourth person on the red team must exert to maintain equilibrium.
In a tug-of-war, equilibrium is achieved when the sum of the forces on each side of the rope is equal.
We can start by finding the sum of the forces on the blue team:
220 N + 340 N + 180 N + 560 N = 1300 N
Next, let's find the sum of the forces on the red team:
250 N + 160 N + 420 N = 830 N
Since the total force on each side of the rope needs to be equal for equilibrium, we can set up the equation:
Total force on blue team = Total force on red team
1300 N = 830 N + Force exerted by the fourth person on the red team
To find the force exerted by the fourth person on the red team, we can rearrange the equation:
Force exerted by the fourth person on the red team = Total force on blue team - Total force on red team
Force exerted by the fourth person on the red team = 1300 N - 830 N
Force exerted by the fourth person on the red team = 470 N
Therefore, the fourth person on the red team must exert a force of 470 N to maintain equilibrium in the tug-of-war.