A pressurized can of whipping cream has an internal pressure of 1.035 atm at 28°C. If it is placed in a freezer at -15°C, what is the new value for its internal pressure?in atm
(P1/T1) = (P2/T2)
Don't forget T must be in kelvin.
I set it up just like that and got kelvins right but still got it wrong
301.15k for T1
258.15k for T2
Answer was 0.887
P1 = 1.035 atm and T1 is 273.15 + 28 = 301.15
P2 = ? and T2 = -15 + 273.15 = 258.15
(1.035/301.15) = (P2/258.15)
P2 = 1.035*258.15/301.15 = 0.887
You must have made an error in solve that proportion. My answer seems to agree.
Sorry I wasn't clear. That was the answer I got. I think my sig figs wrong cause I don't see any with three.
You're right. It's a s.f. thing and I should have caught it. My answer is 0.887216 which I would round to 0.8872
To find the new value for the internal pressure of the can of whipping cream when placed in the freezer, we need to use the ideal gas law equation:
PV = nRT
where:
P is the pressure (in atm)
V is the volume (in liters)
n is the number of moles
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature (in Kelvin)
Step 1: Convert temperatures to Kelvin
The given temperature of the can of whipping cream is 28°C. To convert it to Kelvin, simply add 273 to the Celsius temperature:
T1 = 28°C + 273 = 301 K
The temperature in the freezer is -15°C. Convert it to Kelvin:
T2 = -15°C + 273 = 258 K
Step 2: Use the ideal gas law equation to solve for the new pressure.
Since the number of moles, volume, and gas constant remain constant, we can rewrite the equation as:
P1/T1 = P2/T2
Now, plug in the given values:
1.035 atm / 301 K = P2 / 258 K
Step 3: Solve for P2 (the new pressure)
Cross multiply and solve for P2:
1.035 atm * 258 K = P2 * 301 K
P2 = (1.035 * 258) / 301
P2 ≈ 0.888 atm
Therefore, the new value for the internal pressure of the can of whipping cream, when placed in the freezer at -15°C, is approximately 0.888 atm.