A field is 225 m long and 175 m wide. It has two roads in its centre of uniform width of 5 m, one parallel to its length and the other parallel to its breadth. Find the cost of levelling the at rupees 3 per square metre

I assume you mean leveling the ground for the roads.

3(225*5 + 175*5) = ?

This assumes that the intersection is leveled twice.

To find the cost of leveling the field, we first need to calculate the total area of the field.

The field can be divided into four rectangular areas: two smaller rectangles on the sides and two larger rectangles in the center.

Let's calculate the area of each rectangle:

1. Area of the larger rectangles:
The length of the larger rectangles is the same as the length of the field, minus the width of the two roads (5 m on each side).
Length of larger rectangles = 225 m - 5 m - 5 m = 215 m

The width of the larger rectangles is the same as the breadth of the field.
Width of larger rectangles = 175 m

Area of each larger rectangle = Length x Width = 215 m x 175 m

2. Area of the smaller rectangles:
The length of the smaller rectangles is the same as the breadth of the field, minus the width of the two roads (5 m on each side).
Length of smaller rectangles = 175 m - 5 m - 5 m = 165 m

The width of the smaller rectangles is the same as the width of the field.
Width of smaller rectangles = 175 m

Area of each smaller rectangle = Length x Width = 165 m x 175 m

Now, we can calculate the total area of the field by adding the areas of all four rectangles:

Total area of the field = 2 x Area of larger rectangle + 2 x Area of smaller rectangle

Total area = 2 x (215 m x 175 m) + 2 x (165 m x 175 m)

Next, we can calculate the cost of levelling the field by multiplying the total area by the cost per square meter:

Cost of leveling the field = Total area x Cost per square meter

Cost = Total area x 3 rupees per square meter

Substituting the values and performing the calculations, we can find the final answer.

Rs 5925