gasoline sold in ontario must contain at least 5.00% v/v ethanol? How much gasoline contains 1.50 L of ethanol
(1.5/x)*100 = 5%
so i would solve for x
is the answer 30?
Yes, but you can check these things by substituting and see if the answer you get is 5%.
(1.5/30)*100 = ? Yea! It's 5%.
ok thank you so much!!!
ok thank you so much
To determine the amount of gasoline that contains 1.50 L of ethanol, we need to use the given requirement that gasoline sold in Ontario must contain at least 5.00% v/v (volume/volume) ethanol.
First, let's set up the equation to find the amount of gasoline.
Percentage of ethanol = (Volume of ethanol / Total volume of gasoline) * 100%
Using the given requirement, we can substitute the values as follows:
5.00% = (1.50 L / Total volume of gasoline) * 100%
Now, let's rearrange the equation to solve for the total volume of gasoline:
Total volume of gasoline = (1.50 L / 5.00%) * 100%
Calculating this expression, we get:
Total volume of gasoline = (1.50 L / 0.05) * 100%
= 30 L
Therefore, 1.50 L of ethanol will be mixed with 30 L of gasoline to meet the 5.00% v/v ethanol requirement in Ontario.