The solubility of NaCl at 17 celsisus degrees is 39 g per 100 ml water. If 83 g of NaCl is dissolved in 250ml of water at the same temperature, the resulting solution is: a)unsaturated; b)saturated; c)supersaturated
If solubility is 39 g/100 mL, how many grams will dissolve in 250 mL? That's
39 g x (250 mL/100 mL) = 97.5 g.
The problem states that 83 g has been dissolved; the solution can hold 97.5 so the solution is .......?
To determine if the resulting solution is unsaturated, saturated, or supersaturated, we need to compare the amount of solute (NaCl) in the solution to its maximum solubility at that temperature.
The given solubility of NaCl is 39 g per 100 ml of water at 17 degrees Celsius. We can use this information to calculate the maximum amount of NaCl that can dissolve in 250 ml of water at the same temperature.
Step 1: Calculate the maximum solubility of NaCl in 250 ml of water.
Since the given solubility is expressed per 100 ml, we need to scale it up to 250 ml:
(39 g / 100 ml) x 250 ml = 97.5 g
The maximum amount of NaCl that can dissolve in 250 ml of water at 17 degrees Celsius is 97.5 g.
Step 2: Compare the amount of NaCl dissolved to the maximum solubility.
Given that 83 g of NaCl is dissolved in 250 ml of water, which is less than the calculated maximum solubility of 97.5 g.
Since the amount of solute (83 g) is less than the maximum solubility (97.5 g) at this temperature, the resulting solution is unsaturated.
Therefore, the answer is (a) unsaturated.