solve by using quadratic formula
x^2+2x-35=0
i got
x=10.85 or x=-12.85
x^2+10x+24=0
or
x^2-11x+24=0
and*
x^2+2x-35
x = (-2±√(4+140))/2
= (-2±12)/2
= 5,-7
Not sure how you got your answers, since you declined to show your work...
x^2+10x+24
(x+4)(x+6)
or, using the QF,
(-10±√4)/2
x^2-11x+24
(x-8)(x-3)
or, via QF,
(11±√25)/2
To solve the quadratic equation x^2 + 2x - 35 = 0 using the quadratic formula, you can follow these steps:
Step 1: Write down the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)
Step 2: Identify the coefficients a, b, and c in your equation.
In this case, a = 1, b = 2, and c = -35.
Step 3: Plug these values into the quadratic formula.
x = (-2 ± √(2^2 - 4 * 1 * -35)) / (2 * 1)
Simplifying the formula gives:
x = (-2 ± √(4 + 140)) / 2
x = (-2 ± √144) / 2
x = (-2 ± 12) / 2
Step 4: Solve for x by taking both the positive and negative square root.
For x = (-2 + 12) / 2 = 10 / 2 = 5
For x = (-2 - 12) / 2 = -14 / 2 = -7
Therefore, the solutions to the quadratic equation x^2 + 2x - 35 = 0 are x = 5 and x = -7.