A football punter accelerates a 0.47 kg football from rest to a speed of 6.4 m/s in 0.27 s, what constant force does the punter exert on the ball?
N upward
V = Vo + a*t
V = 6.4 m/s.
Vo = 0
t = 0.27 s.
Solve for a.
F = m*a
3.7037
To find the constant force exerted by the punter on the football, we can use Newton's Second Law of Motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). Mathematically, this can be written as F = ma.
In this case, the mass of the football is given as 0.47 kg, and we need to determine the force exerted by the punter. To find the acceleration, we can use the equation of motion: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
Given:
Initial velocity, u = 0 (since the football is at rest)
Final velocity, v = 6.4 m/s
Time taken, t = 0.27 s
Using the equation v = u + at, we can rearrange it to solve for acceleration:
a = (v - u) / t
Substituting the given values, we have:
a = (6.4 - 0) / 0.27
Calculating this, we find that the acceleration is approximately 23.7 m/s^2.
Now, we can determine the force exerted by the punter using the formula F = ma:
F = 0.47 kg * 23.7 m/s^2
Calculating this, we find that the punter exerts a constant force of approximately 11.14 N upward on the football.