Hydrogen chloride gas can be prepared by the following reaction:
2NaCl(s) + H2SO4(aq) --> 2HCl(g) + Na2SO4(s)
How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?
Well, let's find out how many grams of HCl can be prepared from those amounts.
First, we need to figure out which reactant is limiting. We'll do this by comparing the moles of H2SO4 and NaCl.
From the balanced equation, we see that 2 moles of HCl are produced for every 1 mole of H2SO4. So, if we have 2.00 moles of H2SO4, we'll produce 4.00 moles of HCl.
Next, we look at the moles of NaCl. From the balanced equation, we can see that 2.56 moles of NaCl will produce 5.12 moles of HCl.
Since we produce less moles of HCl from the H2SO4 (4.00 moles) than from the NaCl (5.12 moles), we can conclude that the H2SO4 is the limiting reactant.
Now, we need to convert the moles of HCl to grams. From the molar mass of HCl (36.46 g/mol), we can calculate:
4.00 moles HCl * 36.46 g/mol = 145.84 grams of HCl can be prepared.
So, you can prepare 145.84 grams of HCl. That's a lot of acid! Handle with care!
To determine the amount of HCl that can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl, we need to use the stoichiometry of the balanced equation.
The balanced equation is:
2NaCl(s) + H2SO4(aq) → 2HCl(g) + Na2SO4(s)
From the balanced equation, we can see that 2 moles of NaCl react to form 2 moles of HCl. This means that the ratio of NaCl to HCl is 1:1.
Therefore, the moles of HCl that can be prepared is equal to the moles of NaCl.
Given that there are 2.56 mol of NaCl, 2.56 mol of HCl can be produced.
To calculate the mass of HCl, we need to use its molar mass. The molar mass of HCl is approximately 36.46 g/mol.
So, the mass of HCl that can be prepared is:
Mass of HCl = Moles of HCl × Molar Mass of HCl
= 2.56 mol × 36.46 g/mol
= 93.54 g
Therefore, 93.54 grams of HCl can be prepared from 2.00 moles of H2SO4 and 2.56 moles of NaCl.
To answer this question, we need to use the given balanced chemical equation to determine the stoichiometry of the reaction. This will allow us to calculate the number of moles of HCl produced from the given amounts of H2SO4 and NaCl. Finally, we can convert the moles to grams using the molar mass of HCl.
Step 1: Determine the stoichiometry of the reaction.
According to the balanced equation, 2 moles of NaCl react with 1 mole of H2SO4 to produce 2 moles of HCl. This means that the ratio of NaCl to H2SO4 to HCl is 2:1:2.
Step 2: Convert the given moles into moles of HCl.
Given:
- Moles of H2SO4 = 2.00 mol
- Moles of NaCl = 2.56 mol
Since the ratio of H2SO4 to HCl is 1:2, we can calculate the moles of HCl produced from the moles of H2SO4 using the ratio:
Moles of HCl = (moles of H2SO4) x (2 moles HCl/1 mole H2SO4)
Moles of HCl = 2.00 mol x (2 mol HCl/1 mol H2SO4)
Moles of HCl = 4.00 mol
Since the ratio of NaCl to HCl is 2:2, we can calculate the additional moles of HCl produced from the moles of NaCl using the ratio:
Moles of HCl = (moles of NaCl) x (2 moles HCl/2 moles NaCl)
Moles of HCl = 2.56 mol x (2 mol HCl/2 mol NaCl)
Moles of HCl = 2.56 mol
Step 3: Calculate the grams of HCl produced.
To convert moles of HCl to grams, we need to use the molar mass of HCl, which is 36.46 g/mol.
Grams of HCl = (moles of HCl) x (molar mass of HCl)
Grams of HCl = 4.00 mol x 36.46 g/mol
Grams of HCl = 145.84 g
Therefore, from 2.00 mol H2SO4 and 2.56 mol NaCl, you can prepare 145.84 grams of HCl.
First You need to find out limited regents
here limiting regents is 2.56 mol NaCl
so 2.56g NaCl * 1 mol NaCl/ 58.49 NaCl*2 mol HCl/ 2 mol NaCl* 36.46 g HCl/ 1 mol HCl = 93.50 g