A particle of mass 3.00 kg is projected vertically upward with an initial velocity of 20.0 m/s. Neglecting air resistance, the particle’s kinetic energy when it is 20 m above the initial position is:
i need help
here taking u=20m/s
using v=u-at and finding the total time by taking v=0
we get T=2sec
now at 2sec the distance
S=ut-1/2at^2
thus S=(20)(2)-1/2(10)(4)
=40-20
=20m
thus 20m is its highest point
hence at highest point we know that entier kinetic energy turns into potential energy thus kinetic energy left is zero
To determine the kinetic energy of the particle when it is 20 m above its initial position, we need to calculate the kinetic energy at that specific height.
The kinetic energy (KE) of a particle can be obtained using the formula:
KE = (1/2) * mass * velocity^2
Given:
mass (m) = 3.00 kg
initial velocity (u) = 20.0 m/s
height above initial position (h) = 20 m
To calculate the kinetic energy, we need to find the final velocity of the particle when it reaches a height of 20 m.
Using the laws of motion, we can determine the final velocity (v) using the following equation:
v^2 = u^2 - 2gh
Where:
g = acceleration due to gravity (9.8 m/s^2)
Plugging in the values, we get:
v^2 = (20.0 m/s)^2 - 2 * 9.8 m/s^2 * 20 m
Solving this equation will give us the value of v.
After obtaining the final velocity (v), we can substitute it back into the kinetic energy formula to calculate the kinetic energy at a height of 20 m.