a baseball played 120 games during a season. The ratio of the number of games won to the total number of games played is 2/3. how many games did the team lose during the season?
120/1=2/3 360 divided by 2=180 or 120/x =2/3, 120 divided by 2 = 60
If the ratio is 2:3, then
games won = 2/5 of 120 = 48
So, games lost is 3/5 of 120 = 72
The correct proportion would be
x/120 = 3/5
Consider. If the ratio is 2:3, the
won/lost = 2/3
won = 2/3 lost
lost+won=120
lost + 2/3 lost = 120
5/3 lost = 120
lost = 120 * 3/5 = 72
To find the number of games the team lost during the season, we need to subtract the number of games won from the total number of games played.
We know that the ratio of the number of games won to the total number of games played is 2/3. This means that for every 2 games won, there are 3 games played in total.
We can set up a proportion to solve for the number of games won. Let's call the number of games won "x". So we have:
x/120 = 2/3
To solve for x, we can cross-multiply and solve for x:
3x = 240
x = 80
Therefore, the team won 80 games.
To find the number of games lost, we subtract the number of games won from the total number of games played:
120 - 80 = 40
Therefore, the team lost 40 games during the season.