When 3.2 g of ammonium chloride is dissolved in 75 g of water, the temperature of the solution decreases from 22.8°C to 20.1°C. What is the energy of dissolution of NH4Cl per mole? (The molecular mass of NH4Cl = 53.49 g/mol, and the specific heat of water = 4.18 J/g°C.)
A. 14.8 kJ/mol
B. 0.88 kJ/mol
C. 390 kJ/mol
D. 125 kJ/mol
Could you write he formula and plug in the values.
I get 14.1. Should I got with a.
this is what I got. .0599*4.18*2.7=.6760
I know its not the answer so what did I do wrong
The best way to say it is that you didn't follow the script. Let's do this in two steps.
Step 1 is to calculate the heat of solution (actually cooling of the solution).
q = mass H2O x specific heat H2O x (Tfinal-Tintial)
What is q?
is q 846.45
Exactly. And the unit is J.
Now, that's for 0.0599 mols which you have in your first post. Convert that to J/1 mol and convert that to kJ/mol
0.84645 kJ/0.0599 mol = ? kJ/mol