A store sells small notebooks for $8 and large notebooks for $10. If you buy 6 notebooks and spend $56, how many of each size notebook did you buy?
my answer: 7 small notebooks and 5 large notebooks
is this right?
1-1 THEN ADD 3 TO 6 THEN WHAT YOU WILL HAVE.
THE AWNSER-
To answer this question, we can set up a system of equations. Let's denote the number of small notebooks as s and the number of large notebooks as l.
The given information tells us that the store sells small notebooks for $8 and large notebooks for $10. It also tells us that if you buy 6 notebooks in total, you spend $56.
From this, we can create two equations:
1. s + l = 6 (since you bought a total of 6 notebooks)
2. 8s + 10l = 56 (since the total cost of the notebooks is $56)
To solve these equations, we can use the method of substitution or elimination. Let's use the substitution method here:
From equation (1), we can express s in terms of l by subtracting l from both sides:
s = 6 - l
Now we substitute this value of s into equation (2):
8(6 - l) + 10l = 56
48 - 8l + 10l = 56
2l = 8
l = 4
Substituting this value of l back into equation (1), we find:
s + 4 = 6
s = 2
Therefore, you bought 2 small notebooks and 4 large notebooks, not 7 small notebooks and 5 large notebooks.
If you only bought 6 notebooks, how do you get 7 and 5? You need to read the problems carefully.
x = 6-y
10x + 8y = 56
Substitute 6-y for x and solve.
Let x be the number of notebooks bought for $10. Let y = number of notebooks for $8
Then x + y = 6 and 10x + 8 y = 56
Now solve (: