A 7.28-kilogram bowling ball traveling 8.50 meters per second east collides head-on with a

5.45 kilogram bowling ball traveling 10.0 meters per second west. Determine the magnitude of the
total momentum of the two-ball system after the collision

7.38 kgm/s

9.6

A 1.2-kilogram basketball travelling at 7.5 meters per second hits the back of a 12-kilogram wagon and bounces off a 3.8 meters per second, sending wagon off in the original direction of travel of the ball. How fast is the wagon going?

sry for late reply but @Anonymous that's right thanks so much wanted you to get your thanks *hugs you* thanks alot

To determine the magnitude of the total momentum of the two-ball system after the collision, we need to calculate the momentum of each ball individually and then add them together.

The momentum of an object can be calculated using the formula:

Momentum (p) = mass (m) × velocity (v)

For the first ball (7.28 kg, traveling 8.50 m/s east):
Momentum of the first ball = 7.28 kg × 8.50 m/s = 61.88 kg·m/s (east)

For the second ball (5.45 kg, traveling 10.0 m/s west):
Since the second ball is traveling in the opposite direction, we need to consider its velocity as negative (-10.0 m/s).
Momentum of the second ball = 5.45 kg × (-10.0 m/s) = -54.5 kg·m/s

Now, we can find the total momentum of the two-ball system by adding the individual momenta:
Total Momentum = Momentum of first ball + Momentum of second ball

Total Momentum = 61.88 kg·m/s (east) + (-54.5 kg·m/s)

Adding the individual momenta:

Total Momentum = 7.38 kg·m/s (east)

Therefore, the magnitude of the total momentum of the two-ball system after the collision is 7.38 kg·m/s.