How many molecules are in 0.923 mol of selenium tetrabromide?
1 mol contains 6.022E23 molecules so 0.923 mol will contain ........?
To determine the number of molecules in 0.923 mol of selenium tetrabromide, you can use Avogadro's number, which is 6.022 x 10^23 molecules per mole.
The formula for selenium tetrabromide is SeBr4. It consists of one selenium atom (Se) and four bromine atoms (Br).
To calculate the number of molecules, you need to multiply the number of moles by Avogadro's number. So, the calculation is as follows:
Number of molecules = 0.923 mol * (6.022 x 10^23 molecules/mol)
Now, let's perform the calculation:
Number of molecules = 0.923 mol * (6.022 x 10^23 molecules/mol)
= 5.51 x 10^23 molecules
Therefore, there are approximately 5.51 x 10^23 molecules in 0.923 mol of selenium tetrabromide.
SeBr4
molecules is .923 * avagrodo's number
number of atoms= 5*.923*avag number