Why wouldn't CH3OH be an Arrhenius base?
It does not produce OH^- in solution.
To determine why CH3OH (methanol) would not be considered an Arrhenius base, let's first understand the concept of an Arrhenius base.
The Arrhenius theory states that an Arrhenius base is a substance that, when dissolved in water, releases hydroxide ions (OH-) that contribute to an increase in the concentration of hydroxide ions in the solution. In simpler terms, Arrhenius bases are substances that increase the number of hydroxide ions when they are dissolved in water.
Now, in the case of CH3OH, it is a molecule composed of carbon, hydrogen, and oxygen. It does not have the ability to dissociate or release hydroxide ions in an aqueous solution. Methanol (CH3OH) does not contain any hydroxide ions (OH-) in its structure, which are necessary for it to be considered an Arrhenius base.
To summarize, CH3OH would not be classified as an Arrhenius base because it does not dissociate or release hydroxide ions when dissolved in water.