The population of town A increases from 1,346 to 1,500. In the same period, the population of town B increases from 1,546 to 1,800.
a. Find the percent of increase in population for town A and for town B.
b. Which town had the greater percent of increase?
My answer
town A. 1,346*11.5%=154
1,346+154=1,500
town b 1,546*16.5%=255
1,546+255=1801
town b had the greater percent of increase.
Am I right?
What are the percents of increase?
town A 11.5%
town B 16.5%
I got 11.4% and 16.4%. Yes. B had the greater percent of increase.
but 1,346*11.5%=154 and 1,346+154=1,500
Where did you get 11.5% to start with?
100(1500 - 1346)/1346 = 11.4$
I just started using numbers and it worked. Wouldn't my way work too?
Did you mean 11.4% or 11.4$?
Ooops -- typo
11.4%
You should learn to solve these problems the right way. Not all solutions can be successfully guessed.
Yes, you are almost correct. However, the calculations for the percent of increase are slightly off. Let's go through the correct calculations.
a. To find the percent increase in population for each town, you need to find the difference between the initial population and the final population, divide it by the initial population, and then multiply by 100.
For town A:
Percent increase = ((Final population - Initial population) / Initial population) * 100
= ((1,500 - 1,346) / 1,346) * 100
= (154 / 1,346) * 100
ā 11.45% (rounded to 2 decimal places)
For town B:
Percent increase = ((Final population - Initial population) / Initial population) * 100
= ((1,800 - 1,546) / 1,546) * 100
= (254 / 1,546) * 100
ā 16.45% (rounded to 2 decimal places)
b. To compare the percent increase, you can see that town B had a slightly higher percent increase than town A.
Therefore, your answer for part b is correct. Town B had the greater percent of increase in population.