100.0 mL of a dilute NaCl(aq) solution is heated in an open beaker. After 15 minutes the burner is turned off. Which of the following is true of the resulting solution?
a
more concentrated than the initial solution
b
less saturated than the initial solution
c
less concentrated than the initial solution
d
more miscible than the initial solution
Like a lot of questions this one is not well thought out. Did the solution boil? I'm assuming it did not.
Then I would answer b. If it boiled for a very short time there are two answers, b and a
To determine which of the given options is true of the resulting solution, let's analyze the process that took place:
1. A dilute NaCl(aq) solution was heated in an open beaker.
- When the solution is heated, some of the water molecules will evaporate as steam due to the increase in temperature.
- The NaCl (solute) will not evaporate since it has a higher boiling point than water.
2. After 15 minutes, the burner is turned off.
- Once the burner is turned off, the solution will start to cool down.
Based on these steps, we can deduce the following:
1. The water component of the solution evaporated, leaving behind a higher concentration of NaCl.
- This means that the resulting solution is more concentrated than the initial solution.
2. The cooling process does not affect the saturation level of the solution.
- Saturation refers to the maximum amount of solute that can dissolve in a given amount of solvent, which does not change with temperature.
- Therefore, the resulting solution will have the same saturation level as the initial solution.
Therefore, the correct answer is (a) the resulting solution is more concentrated than the initial solution.