As part of a safety investigation, two 1200kg cars traveling at 24m/s are crashed into different barriers.
Find the average force exerted on the car that hits a concrete barrier and takes 0.16s to stop.
To find the average force exerted on the car that hits a concrete barrier, we can use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (m) over time (t).
Momentum is calculated by multiplying the mass (m) of an object by its velocity (v). In this case, the mass of the car is given as 1200 kg and the velocity is given as 24 m/s.
1. Calculate the initial momentum (p_initial) of the car:
p_initial = mass × velocity
p_initial = 1200 kg × 24 m/s
2. The car takes 0.16 seconds to stop, so we need to calculate the final velocity (v_final). Assuming the car comes to a complete stop, the final velocity will be zero.
3. Calculate the change in momentum (Δp):
Δp = p_final - p_initial
Since the final velocity is zero, the change in momentum is simply equal to the negative initial momentum:
Δp = -p_initial
4. Calculate the average force (F) exerted on the car using Newton's second law of motion:
F = Δp / t
F = (-p_initial) / t
Plug in the given values to calculate the average force.
V = Vo + a*t
V = 0
Vo = 24 m/s
t = 0.16 s.
Solve for a.(It will be negative)
F = M*a