Conductivity experiments indicate that tetraamminedichloropalladium (IV) chloride is composed of 3 moles of ions per mole of compound. When silver nitrate solution is added to a solution of the palladium compound, 2 moles of silver chloride per mole of compound are precipitated rapidly. What is the probable structure of the complex ion?
A. octahedral
B. square planar
C. Tetrahedral
D. Linear
E. Trigonal planar
You can see from the site below that [Pd(CO)4]^2+ is square planar; probably this is dsp2 also. Its structure with two ionizable Cl^- ions would be [Pd(NH3)4Cl2]Cl2. The palladium carbonyl complex was the closest I could come on the web.
http://papadantonakis.com/images/b/b7/Coordination_Compounds.pdf
To determine the probable structure of the complex ion, we need to analyze the information given and make use of the concept of stoichiometry.
According to the information provided, the tetraamminedichloropalladium (IV) chloride compound consists of 3 moles of ions per mole of compound in its solution. This suggests that the palladium compound has a charge of +3.
Now, when silver nitrate solution is added to the palladium compound, it forms silver chloride precipitate. It is mentioned that 2 moles of silver chloride per mole of the compound are rapidly precipitated. This indicates that each mole of the palladium compound must contain two chloride ions.
Considering the fact that the palladium has a +3 charge and there are two chloride ions, one possible structure that satisfies these conditions is a square planar geometry. In this geometry, the palladium ion is surrounded by four ligands, which in this case are four ammonia molecules (tetraammine), and two chloride ions.
Therefore, the probable structure of the complex ion is square planar (B).