i/3 rd of diagonal of square is 3 route 2. find the side of squre.

Please proof-read your post before sending it

route = root
squre = square
i/3 = 1/3 ??

So if 1/3 of the diagonal is 3√2, then the diagonal is 9√2

let the side of the square be x
x^2 + x^2 = (9√2)^2
2x^2 = 162
x^2 = 81
x = √81 = 9