A 92 kg clock initially at rest on a horizontal floor requires a 656 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant speed.

Wc = M*g = 92kg * 9.8N/kg = 902 N. =

wt. of the clock.

Fap-Fs = M*a
656 - Fs = M*0 = 0
Fs = 656 N. = Force of static friction.

us = Fap/Wc = 656/902 = 0.727

uk = 560/902 = 0.621

To find the coefficient of kinetic friction between the clock and the floor, we can use the formula:

μ = F_k / N

where μ is the coefficient of kinetic friction, F_k is the force of kinetic friction, and N is the normal force.

1. First, we need to find the normal force acting on the clock. Since the clock is on a horizontal floor and there is no vertical acceleration or vertical motion, the normal force is equal in magnitude and opposite in direction to the gravitational force acting on the clock.

N = mg

where m is the mass of the clock and g is the acceleration due to gravity.

N = (92 kg) * (9.8 m/s^2)
N = 901.6 N

2. Now, we can calculate the force of kinetic friction.

F_k = F_applied - F_net

where F_applied is the applied force to set the clock in motion and F_net is the net force acting on the clock when it is moving at a constant speed.

F_applied = 656 N
F_net = 560 N

F_k = F_applied - F_net
F_k = 656 N - 560 N
F_k = 96 N

3. Finally, we can calculate the coefficient of kinetic friction.

μ = F_k / N
μ = 96 N / 901.6 N

μ ≈ 0.1065

Therefore, the coefficient of kinetic friction between the clock and the floor is approximately 0.1065.