What is the final volume of NaOH solution prepared from 200.0mL of 0.500M NaOH if you wanted the final concentration to be 0.200M ?
M1V1=M2V2
(200)(0.500)=(.200)x
x=500 mL
M1 is actually 0.5 and V1 is 200! My mistake there.
To solve this problem, we can use the equation for dilution:
C1V1 = C2V2
Where:
C1 is the initial concentration of the solution
V1 is the initial volume of the solution
C2 is the final concentration of the solution
V2 is the final volume of the solution
In this case, we have:
C1 = 0.500 M (initial concentration)
V1 = 200.0 mL (initial volume)
C2 = 0.200 M (final concentration)
V2 = ? (final volume, what we need to find)
Plugging these values into the equation:
0.500 M * 200.0 mL = 0.200 M * V2
Now, let's solve for V2:
V2 = (0.500 M * 200.0 mL) / 0.200 M
V2 = 100.0 mL
Therefore, the final volume of the NaOH solution would be 100.0 mL.