. If f(x) = {x^2+3x-1, x<=2 and -3bx+3, x<2 , find the value of b in order for f to be continuous
well we need the limit from both sides to be the same.
f(2) = 2^2+3*2-1 = 9
So, we need
-3bx+3 = 9 when x=2
-3b*2+3 = 9
-6b = 6
b = -1
f(2) = 2^2+3*2-1 = 9
So, we need
-3bx+3 = 9 when x=2
-3b*2+3 = 9
-6b = 6
b = -1