Determine how many milliliters of 0.310 M HClO4 will be required to neutralize 52.37g Ca(OH)2 according to the reaction:
2HClO4 + Ca(OH)2 ---> Ca(ClO4)2 + 2 H2O
mols Ca(OH)2 = M x L = ?
Convert mols Ca(OH)2 to mols HClO4 using the coefficients in the balanced equation.
Then M HClO4 = mols HClO4/L HClO4. You know mols and M HClO4, solve for L HClO4 and convert to mL.