with what speed does a hammer dropped from a height of 23 m strike the ground?

gpe=Ke

mgh=1/2 m v^2

v=sqrt(2gh)

To calculate the speed at which a hammer strikes the ground when dropped from a height of 23 meters, we can use the equation for the final velocity of a falling object:

vf = sqrt(2 * g * h)

Where:
vf is the final velocity (speed) at which the object strikes the ground,
g is the acceleration due to gravity (approximately 9.8 m/s²),
h is the height from which the object is dropped (in this case, 23 meters).

Substituting the given values into the equation, we can solve for vf:

vf = sqrt(2 * 9.8 * 23) ≈ 20.2 m/s

Therefore, the hammer will strike the ground with a speed of approximately 20.2 meters per second.