How can I convert a rate constant from mol to t/M.I have 0.00012 mol of AcH

present at 5min .Know I want to calculate the concentration at this time ( [AcH]t / M ) . How would I work this out .Please help this is for a lab writeup for tomorrow .

To convert a rate constant from mol to t/M, you need to determine the molar concentration of the substance in question. In your case, you want to calculate the concentration of AcH at a specific time.

To calculate the concentration of AcH at the given time, you need two pieces of information: the initial amount of AcH and the volume of the solution. Let's assume you have the initial amount of AcH in moles and the volume of the solution in liters.

1. Calculate the molar concentration (C) of AcH using the initial amount (n) and the volume (V) of the solution:
C = n / V

2. Use the rate constant (k) formula to calculate the concentration at a specific time (t):
[AcH]t = [AcH]0 * e^(-k * t)

Where:
[AcH]t is the concentration of AcH at time t
[AcH]0 is the initial concentration of AcH (calculated in step 1)
k is the rate constant
t is the time at which you want to calculate the concentration

Make sure the units of time are consistent. Based on your question, it seems you have the rate constant in mol. min^-1, so you need to use minutes as the unit for time.

3. Plug in the values and calculate the concentration at the given time.

For example, assume you have an initial amount of 0.00012 mol of AcH and a volume of the solution of 1 liter. Let's say you want to calculate the concentration at 5 minutes using a rate constant of 0.01 mol. min^-1.

Step 1:
C = 0.00012 mol / 1 L = 0.00012 M

Step 2:
[AcH]t = 0.00012 M * e^(-0.01 mol. min^-1 * 5 min)

Step 3:
Calculate the exponential term:
e^(-0.01 * 5) ≈ 0.60653

[AcH]t = 0.00012 M * 0.60653 ≈ 0.0000728 M

Therefore, the concentration of AcH at 5 minutes would be approximately 0.0000728 M.