I did a titiration expriment and I need

to work out how much Hcl is in the sample (NaOH). The expriment was testing the rate of ester hydrolysis . I was wondering if the the amount of Hcl present is the same as NaOH added due to the equivalence of the acid and base but I also know that the Hcl present needs to be constant as it's the catalyst. I am really confused as to what to do .Lets I had 0.0025 mol of NaOH , how would I go about working out the amount of Hcl in the sample.
Please help me !!!!

I am unable from your post to know exactly what you're doing; however, in a hydrolysis of an ester you produce an alcohol and an acid. I would assume that the NaOH titration is to determine how much acid (total, not just HCl) has been produced. My best guess is that the total NaOH minus the HCl present (since that is supposed to be constant) = mols of the acid producd in the hydrolysis. As the experiment progresses, the amount of organic acid produced is increasing and that gives yous the rate.