a peak is sighted at an angle of 27 degree 45 min. 1000ft nearer its angle of elevation is 31 degree 30 min.find the height of the peak
If the nearer observation point is at distance x, and the peak has height h, then we have
h/x = tan 31°30'
h/(x+1000) = tan 27°45'
Now eliminate x and solve for h.