10 A color candy was chosen randomly out of a bag. Below are the results:
Color Probability
Blue 0.30
Red 0.10
Green 0.15
Yellow 0.20
Orange ???
a. What is the probability of choosing a yellow candy?
b. What is the probability that the candy is blue, red, or green?
c. What is the probability of choosing an orange candy?
a. .20
b. Either-or probabilities are found by adding the individual probabilities.
c. 1 - .3 - .1 - .15 - .2 = ?
To find the probability of each candy color, you need to add up all the probabilities and ensure they sum up to 1.
a. To find the probability of choosing a yellow candy, you simply look at the corresponding probability given in the table. In this case, the probability of choosing a yellow candy is 0.20 or 20%.
b. To find the probability that the candy is blue, red, or green, you need to add up their individual probabilities. According to the table, the probability of blue candy is 0.30, the probability of red candy is 0.10, and the probability of green candy is 0.15. By summing these probabilities, you get 0.30 + 0.10 + 0.15 = 0.55 or 55%.
c. You might have noticed that the probability for the orange candy is missing in the given table. However, since the total probability must sum up to 1, you can calculate the missing probability by subtracting the sum of the probabilities of the other colors from 1. So, 1 - (0.30 + 0.10 + 0.15 + 0.20) = 1 - 0.75 = 0.25 or 25%.
So, the probability of choosing an orange candy is 0.25 or 25%.