What volume of a 0.550 M solution of potassium hydroxide can be made with 14.3 g of potassium hydroxide? (Ignore significant figures for this problem.)
KOH = 39+16+1 = 56 grams/mol
14.3/56 = .255 mols
.255/V = .55/1
V = .464 Liter
answer
Well, potassium hydroxide is quite the joker. It's like this solution is trying to find its perfect fit. So, to figure out the volume of the solution, you're going to need a little chemistry math.
First, let's find the molar mass of potassium hydroxide. We've got 1 potassium atom (K) with a molar mass of 39.10 g/mol, 1 oxygen atom (O) with a molar mass of 16.00 g/mol, and 1 hydrogen atom (H) with a molar mass of 1.01 g/mol. Add all those up, and you've got a total molar mass of 56.11 g/mol for potassium hydroxide.
Next, we convert the grams of potassium hydroxide you have into moles by using the formula:
moles = mass / molar mass
Applying this formula, we get:
moles = 14.3 g / 56.11 g/mol
Now, we can find the volume by using the molarity formula:
Molarity = moles / volume
Rearranging the formula to solve for volume, we get:
volume = moles / Molarity
Plugging in the values, we have:
volume = (14.3 g / 56.11 g/mol) / 0.550 mol/L
Crunching the numbers, you'll find the volume of the solution. But remember, laughter is the best medicine, so make sure to have a good laugh while you calculate. After all, chemistry can be quite the clown!
To determine the volume of the solution, we need to use the equation:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's calculate the number of moles of potassium hydroxide (KOH) using its molar mass.
The molar mass of KOH is:
K (39.10 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 56.11 g/mol
Now, we can calculate the number of moles of KOH using the following formula:
moles of KOH = mass of KOH / molar mass of KOH
moles of KOH = 14.3 g / 56.11 g/mol ≈ 0.255 mol
Next, we can rearrange the equation for molarity to solve for the volume of the solution:
volume of solution (in liters) = moles of solute / molarity
volume of solution = 0.255 mol / 0.550 mol/L ≈ 0.464 L
Therefore, the volume of the 0.550 M solution that can be made with 14.3 g of potassium hydroxide is approximately 0.464 liters (or 464 milliliters).
To find the volume of a solution, we need to use the formula:
Volume (in liters) = mass of solute (in grams) / molarity (in moles per liter)
First, we need to calculate the number of moles of potassium hydroxide (KOH) using its molar mass. The molar mass of KOH is:
K (potassium) = 39.10 g/mol
O (oxygen) = 16.00 g/mol
H (hydrogen) = 1.01 g/mol
Adding these up, we get:
39.10 g/mol + 16.00 g/mol + 1.01 g/mol = 56.11 g/mol
Now, we can calculate the number of moles of KOH:
Moles of KOH = mass of KOH / molar mass of KOH
Moles of KOH = 14.3 g / 56.11 g/mol
Next, we need to use the molarity to find the volume of the solution. The molarity (M) is given as 0.550 moles per liter (M).
Using the formula:
Volume (in liters) = moles of KOH / molarity
Substituting the values:
Volume (in liters) = 14.3 g / 56.11 g/mol / 0.550 mol/L
Now we can solve for the volume of the solution in liters.