In humans, the allele for brown eyes is dominant to the allele for blue eyes. If a man with blue eyes and a woman with brown eyes who is homozygous for eye color have children, what is the probability of having a child with blue eyes?

Here are the choices:
25 percent, 100 percent, 50 percent, 0 percent

Use a Punnett square. Dad is bb and mom is BB.

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To determine the probability of having a child with blue eyes, we need to consider the genetic makeup of both parents. Let's break down the information provided:

1. The man has blue eyes, which means he has two copies of the recessive allele for blue eyes, referred to as "bb."

2. The woman has brown eyes and is homozygous for eye color, meaning she has two copies of the dominant allele for brown eyes, referred to as "BB."

Based on this information, we can establish the possible genotypes for the parents:

The man's genotype: bb
The woman's genotype: BB

Using Punnett Square analysis, we can determine the genotypes and phenotypes of their potential offspring. The Punnett Square for this scenario would look like this:

| B | B |
-----------------------
b | Bb | Bb |
-----------------------
b | Bb | Bb |

From the Punnett Square, we see that all the offspring will have the genotype "Bb," which corresponds to the phenotype of brown eyes.

Therefore, the probability of having a child with blue eyes in this specific scenario is 0 percent.