Car 1 going northward (direction 90 degrees) at 14 m/s in an SUV weighing 2300 kg. car 2 going southwest (direction 225 degrees) at 16 m/s in a car that weighs 1600 kg. it is a completely inelastic collision. What is the direction and speed of the two vehicles immediately after the collision.
Help!!
So far I have 2300<14sin90, 14cos90> and 1600<16sin225, 16sin225>. I don't know what to do with this and where to place it into the equation.
before
North (y) momentum =2300(14) - 1600 (16) cos(270-225)
= 32,200 - 18,101 = 14,098 kg m/s
East(x) momentum = 0 =18,101 = -18,101
after
same momentum, but mass is 2300+1600 = 3900 kg
East (x) = 3900 * Vx = -18,101
North (y) = 3900*Vy = 14,098
so Vx = -4.64 m/s
Vy = 3.61 m/s