Question

What mass of pure silver would you obtain from 85.0 g of AgNO3?

I got 53.55 g is that correct?

Answer 1

Ag = 108 g/mol

N =14 g/mol
O3 = 3*16 = 48 g/mol

so AgNO3 = 170 g/mol of which 108 is silver

(108/170)(85) = 54, close enough