1. Which salt is LEAST soluble at 0 ºC?

2. How many grams of sodium nitrate, NaNO3, are soluble in 100 g of water at 10 ºC?
3. When 50 grams of potassium chloride, KCl, is dissolved in 100 grams of water at 50 ºC, the solution can be correctly described as:
A. saturated
B. supersaturated
C. unsaturated
4. When 20 grams of potassium chlorate, KClO3, is dissolved in 100 grams of water at 80 ºC, the solution can be correctly described as:
A. unsaturated
B. saturated
C. supersaturated
5. At approximately what temperature does the solubility of sodium chloride, NaCl, match the solubility of potassium dichromate, K2Cr2O7?
6. A solution of potassium chlorate, KClO3, has 20 grams of the salt dissolved in 100 grams of water at 70 ºC. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?
7. A beaker containing 80 grams of lead(II) nitrate, Pb(NO3)2, in 100 grams of water has a temperature of 30 ºC. Approximately how many grams of the salt are undissolved, on the bottom of the beaker?
8. Which salt is LEAST soluble at 50 ºC?
9. How many grams K2Cr2O7 would you need to add to 100 grams of water at 80 ºC to make a saturated solution?
10. You heat a saturated solution of KClO3 from 30 ºC to 90 ºC. How much more solute were you able to add to the new saturated solution?

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You must have graphs for solubility or tables of solubility. Without those I can't help.

1. The salt that is least soluble at 0 ºC is likely to be silver chloride (AgCl).

2. The solubility of sodium nitrate, NaNO3, in water at 10 ºC can be found using a solubility table or data. Let's assume that the solubility of NaNO3 at 10 ºC is 180 g/100 g of water. Therefore, 100 g of water can dissolve 180 g of NaNO3.

3. To determine whether the solution of 50 grams of potassium chloride (KCl) in 100 grams of water at 50 ºC is saturated, unsaturated, or supersaturated, we need to compare it against the solubility of KCl at that temperature. If the solubility of KCl at 50 ºC is 40 g/100 g of water, and we have 50 g of KCl dissolved in 100 g of water, the solution is unsaturated because it can still hold more KCl.

4. Similar to question 3, we need to compare the amount of potassium chlorate (KClO3) dissolved in 100 grams of water at 80 ºC with its solubility at that temperature. If the solubility of KClO3 at 80 ºC is 100 g/100 g of water, and we have only 20 g of KClO3 dissolved in 100 g of water, the solution is unsaturated because it can hold more KClO3.

5. The solubilities of sodium chloride (NaCl) and potassium dichromate (K2Cr2O7) are likely to match at around 50 ºC. Please note that the specific temperature of solubility matching can vary depending on the solubility data used.

6. To determine how much more potassium chlorate (KClO3) can be added to the solution before reaching the saturation point, we need to compare the already dissolved amount with the solubility of KClO3 at that temperature. If the solubility of KClO3 at 70 ºC is 150 g/100 g of water, and we already have 20 g of KClO3 dissolved in 100 g of water, we can add approximately 130 g more of KClO3 before reaching saturation.

7. Assuming the lead(II) nitrate (Pb(NO3)2) in the beaker is completely dissolved, we can say that all 80 g of Pb(NO3)2 are in the solution. Therefore, there are no undissolved grams of the salt on the bottom of the beaker.

8. The salt that is least soluble at 50 ºC can vary, but one example is calcium hydroxide (Ca(OH)2).

9. To make a saturated solution of potassium dichromate (K2Cr2O7) in water at 80 ºC, we need to know the solubility of K2Cr2O7 at that temperature. Assume the solubility is 100 g/100 g of water at 80 ºC. Therefore, to make a saturated solution, we need to add 100 g of K2Cr2O7 to 100 g of water at 80 ºC.

10. When you heat a saturated solution of potassium chlorate (KClO3) from 30 ºC to 90 ºC, the solubility of KClO3 increases. The exact increase in solubility will depend on the solubility data. Let's assume that the solubility of KClO3 at 90 ºC is twice that at 30 ºC. If you initially had 100 g of KClO3 dissolved in the saturated solution at 30 ºC, you would be able to add an additional 100 g of KClO3 to the new saturated solution at 90 ºC.

1. To determine which salt is least soluble at 0 ºC, you can refer to a solubility table or solubility chart. These resources provide information on the solubility of different salts at various temperatures. Look for the solubility values of salts at 0 ºC and compare them. The salt with the lowest solubility value at 0 ºC will be the least soluble.

2. To find out how many grams of sodium nitrate (NaNO3) are soluble in 100 g of water at 10 ºC, you can consult a solubility table or chart for the solubility of NaNO3 at 10 ºC. The solubility is usually given in grams of solute per 100 grams of water. Multiply the solubility value by 100 g to find the number of grams of NaNO3 that can be dissolved in 100 g of water.

3. To determine the correct description of a solution made by dissolving 50 grams of potassium chloride (KCl) in 100 grams of water at 50 ºC, you need to know the solubility of KCl at that temperature. Compare the amount of KCl dissolved (50 g) to the maximum amount that can dissolve in that amount of water at that temperature. If 50 g of KCl is the maximum that can dissolve, the solution is saturated. If less than 50 g is dissolved, the solution is unsaturated. If more than 50 g is dissolved, the solution is supersaturated.

4. Similar to question 3, to determine the description of a solution made by dissolving 20 grams of potassium chlorate (KClO3) in 100 grams of water at 80 ºC, you need to compare the amount of KClO3 dissolved to the maximum solubility at that temperature. If 20 g is less than the maximum solubility, the solution is unsaturated. If it is equal to the maximum solubility, the solution is saturated. If it exceeds the maximum solubility, the solution is supersaturated.

5. To find the approximate temperature at which the solubility of sodium chloride (NaCl) matches the solubility of potassium dichromate (K2Cr2O7), you can compare the solubility values of both compounds at different temperatures using a solubility table or chart. Look for the temperature at which the solubility values of NaCl and K2Cr2O7 are equal or closest to each other.

6. To determine how many more grams of potassium chlorate (KClO3) can be added to a solution before reaching the saturation point, you need to know the solubility of KClO3 at the given temperature (70 ºC). Subtract the amount of KClO3 already dissolved in the solution (20 g) from the maximum solubility at that temperature to find out how much more can be dissolved without exceeding saturation.

7. To estimate the amount of undissolved lead(II) nitrate (Pb(NO3)2) in the beaker, you need to determine the maximum solubility of Pb(NO3)2 at the given temperature (30 ºC) using a solubility table or chart. Subtract the amount of Pb(NO3)2 already dissolved in the solution (80 g) from the maximum solubility to find the approximate amount that remains undissolved.

8. To identify the salt that is least soluble at 50 ºC, you can consult a solubility table or chart that provides solubility data for different salts at 50 ºC. Compare the solubility values and choose the salt with the lowest solubility at that temperature.

9. To determine the number of grams of K2Cr2O7 needed to make a saturated solution in 100 grams of water at 80 ºC, you need to know the solubility of K2Cr2O7 at that temperature. Consult a solubility table or chart to find the solubility value in grams of solute per 100 grams of water. The solubility value represents the maximum amount that can be dissolved, so it specifies the amount of K2Cr2O7 required to make a saturated solution.

10. To calculate the additional solute that can be added when heating a saturated solution of KClO3, you need to compare the solubility of KClO3 at 30 ºC and 90 ºC. Determine the difference between the two solubility values to find out how much more KClO3 can dissolve in the higher temperature solution. This difference represents the additional solute that can be added.