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What mass of pure silver would you obtain from 85.0 g of AgNO3?
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The answer i got is 53.55 g
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yes
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Similar Questions
What mass of pure silver would you obtain from 85.0 g of AgNO3?
I got 53.55 g is that correct?
Top answer:
Ag = 108 g/mol N =14 g/mol O3 = 3*16 = 48 g/mol so AgNO3 = 170 g/mol of which 108 is silver
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AgNO3 solutions are often used to plate silver onto other metals.
What is the maximum amount of silver in grams that can be
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If the density of the solution is 1.00 g/mL (and it may not be) it has a mass of 4200 grams. That x
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AgNO3 solutions are often used to plate silver onto other metals. What is the maximum amount of silver in grams that can be
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2.22
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find the mass of silver chloride formed from 33.2ml of a 0.100M solution of silver nitrate and 200ml of 0.200M solution of
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To find the mass of silver chloride formed, we can use mass-to-mass calculations. Here's how you can
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a) A current of 1.50 Amperes passes through a solution of AgNO3 for 3.0 hours. What mass, in grams, of silver collects on the
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All three are based on the fact that 1 grams equivalent weight is deposited with 96,485 coulombs a).
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What mass of silver nitrate (AgNO3) is required to prepare 400 g of a 3.50% solution of
AgNO3
Top answer:
3.50% AgNO3 means 3.50g AgNO3/100 g soln. You want 400 g; therefore, you will need 3.50g x (400/100)
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A solution is 36% silver nitrate (AgNO3) by mass. The density of this solution is 1.44
g/mL. The formula weight of AgNO3 is 170
Top answer:
36% AgNO3 means 36 g AgNO3/100 g solution. 36 g = 36/170 moles = ?? 100 g solution = volume x
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What mass of silver nitrate (AgNO3) is re-
quired to prepare 400 g of a 3.50% solution of AgNO3? 1. 14 g 2. 0.00875 g 3. 114.28 g
Top answer:
percent what? w/w; w/v, v/v, etc. I assume this is mass percent. (g AgNO3/400 g soln)*100 = 3.50
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Suppose you wanted to find out how many milliliters
of 1.0 M AgNO3 are needed to provide 169.88 g of pure AgNO3. a. What is step
Top answer:
call me
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what mass of silver nitrate (AgNO3) is required to prepare 400 grams of a 3.50% solution of AgNO3?
Options: 1. 0.00875 g 2.
Top answer:
14g I put it in and it's right.
Read more.
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