An aircraft landing on an aircrafts carrier is brought to a complete stop from an initial of 215km/h in 2.7 seconds. What is its acceleration in m/s2?
same as your last question
0 = 215/3.6 + a (2.7)
a will be negative because braking
Calculat
What is slope
To find the acceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
First, let's convert the initial velocity from km/h to m/s. Since 1 km/h is equal to 1000 m/3600 s, we have:
initial velocity = 215 km/h * (1000 m/3600 s) = 59.722 m/s (rounded to three decimal places)
Now we can use the formula:
acceleration = (final velocity - initial velocity) / time
Given that the final velocity is 0 m/s (since the aircraft comes to a complete stop), the time is 2.7 seconds, and the initial velocity is 59.722 m/s, we have:
acceleration = (0 m/s - 59.722 m/s) / 2.7 s = -22.075 m/s² (rounded to three decimal places)
Therefore, the acceleration of the aircraft is approximately -22.075 m/s². The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.